When I first attempted this problem, I chose to work with number 9 (as 9 is my favourite number) in the corner box. Here is one 3x3 square I got stuck on. I found that this did not work because I would need the diagonal for numbers less than 6; 9+6 does not allow for a number in the final box.
9 |
2 |
4 |
1 |
6 |
|
5 |
|
|
I ran into this same
problem when 9 was in the middle. There were just too many “open boxes” around
9 that needed two numbers that added to 6 without repeating numbers.
|
1 |
4 |
|
9 |
|
2 |
5 |
|
Finally, I achieved a
solution when 9 was not the middle or corner piece.
2 |
9 |
4 |
7 |
5 |
3 |
6 |
1 |
8 |
Good! (Interesting how our favourite numbers can skew our approaches too!)
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